0.2x^2-6x+7.2=0

Solution for 0.2x^2-6x+7.2=0 equation:

0.2x^2-6x+7.2=0

a = 0.2; b = -6; c = +7.2;
Δ = b2-4ac
Δ = -62-4·0.2·7.2
Δ = 30.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{30.24}}{2*0.2}=\frac{6-\sqrt{30.24}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{30.24}}{2*0.2}=\frac{6+\sqrt{30.24}}{0.4}
$